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Acceleration of Racquet Take Back

 

Novak Djokovic

Given:

vf = 5.30 m/s

vi = 1.47 m/s

t = 0.58 m/s

 

Required: 

a (acceleration)

Analyze: 

 

 

 

 

Solve: 

a = (5.30 m/s - 1.47 m/s)/0.58s

    = 6.60 m/s^2

 

Present: 

Therefore, Novak Djokovic's takeback speed is 6.60 m/s^2

Acceleration of Racquet

Given:

       = 8.46

t = 0.20 s

 

Required: 

a (acceleration)

Analyze: 

 

 

 

 

Solve: 

a = (8.456m/s)/0.2s

    = 42.28 m/s^2

 

Present: 

Therefore, Novak Djokovic's racquet speed is 42.28 m/s^2.

Acceleration of Ball

Given:

    v = average of velocities

= 9.1 m/s

 

t = 0.1 s

 

Required: 

a (acceleration)

Analyze: 

 

 

 

Solve: 

a = ((13.87m/s +9.11m/s +7.48m/s + 5.59m/s)/4)/0.1

    = 90.1 m/s^2

 

Present: 

Therefore, the acceleration of the ball that Novak Djokovic hits on his forehand is 90.1 m/s^2

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